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求tAn(7π/4)的三角函数值

tan(-17π/6)=√3/3≈0.577

cos9π/4=cos(2π+π/4)=cosπ/4=根号2/2 sin780°=sin(720°+60°)=sin60°=根号3/2 tan(-7π/6)=tan(-2π+5π/6)=tan(π-π/6)=-tanπ/6=-根号3/3

解: -17π/6=-18π/6 + π/6 =-3π +π/6 因此: tan(-17π/6)=tan(-3π +π/6)=tan(-π+π/6)=tan(-5π/6)=-tan(5π/6)=-tan(π - π/6)=tan(π/6) =√3/3 -31π/4=-32π/4+π/4=-8π+π/4 因此: tan(-8π+π/4)=tanπ/4=1

三角函数的值: sin0=sin0°=0 cos0=cos0°=1 tan0=tan0°=0 sin15=0.650;sin15°=(√6-√2)/4 cos15=-0.759;cos15°=(√6+√2)/4 tan15=-0.855;tan15°=2-√3 sin30=-0.988;sin30°=1/2 cos30=0.154;cos30°=√3/2 tan30=-6.405;tan30°=√3/3 sin45=0...

tan(14π/3) =tan(4π+2π/3) =tan(2π/3) =-√3 行家正解,不明白可以追问!祝您学习进步 满意请点击下面的【选为满意回答】按钮,O(∩_∩)O谢谢

sinπ/8 = √{(1-cosπ/4)/2} = √{(1-√2/2)/2} = √(2-√2)/2 cosπ/8 = √{(1+cosπ/4)/2} = √{(1+√2/2)/2} = √(2+√2)/2 tanπ/8 = (1-cosπ/4)/(sinπ/4) = (1-√2/2)/(√2/2) = √2-1 sin7π/8 = sinπ/8 = √(2-√2)/2 c os7π/8 = -cosπ/8 = -√(2+√2)/2 t an7π...

因为tanα=y/x所以按照象限坐标区分符号就好

tan(-5π/18) =-tan(5π/18) =-tan50° ≈-1.1918

常用的诱导公式有以下几组: 公式一:设α为任意角,终边相同的角的同一三角函数的值相等: sin(2kπ+α)=sinα (k∈Z) cos(2kπ+α)=cosα (k...

0度角:tan0°=0,arctan0=0° 30度角:tan30°=√3/3,arctan(√3/3)=30° 45度角:tan45°=1,arctan1=45° 60度角:tan60°=√3,arctan√3=60° 扩展资料: 设α为任意角,终边相同的角的同一三角函数的值相等:tan(2kπ+α)=tanα 设α为任意角,π+α的三角...

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